A suitcase with measures 80 cm x 48 cm x 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Solution:

Given

Length of suitcase box (l)= 80 cm,

Breadth of suitcase box (b) = 48 cm

Height of cuboidal box (h) = 24 cm

Find out

We have to find out how many meters of tarpaulin is required

Formula

Total surface area of suitcase box = 2 × (lb + bh + hl)

= 2 × (80 × 48 + 48 × 24 + 24 × 80)

= 2 × (3840 + 1152 + 1920)

= 2 × 6912

= 13824 cm²

Hence, the Total surface area of the suitcase box is 13824 cm²

As suitcase is fully covered by tarpaulin

Area of Tarpaulin cloth = Surface area of suitcase

(l × b) = 13824

(l × 96) = 13824

l = 144m

Required tarpaulin for 100 suitcases = 144 × 100 = 14400 cm = 144 m

Answer

Hence, the tarpaulin cloth required to cover 100 suitcases is 144 m.

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