A thin circular ring of the area A is held perpendicular to a uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of the circuit is R. When the ring suddenly squeezed to zero areas, the charge flowing through the galvanometer is: A) BR/A B) (AB)/R C) ABR D) E2A/R2 E) None

Answer: B) (AB)/R

As we know,

Q = It

Now,

I = induced EMF/R

EMF = (-0-BA)/t

I = BA/Rt

Q = (BA/Rt) x t

Q = BA/R

Was this answer helpful?

 
   

0 (0)

(1)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question