In its primary winding, a transformer has 500 turns.

In its secondary winding, a transformer has 1000 turns.

The primary voltage is 200 V

In usual rotation =

\(\frac{V_{s}}{V_{p}} = \frac{N_{s}}{N_{p}}\) \(\Rightarrow V_{s} = V_{p} * \frac{N_{s}}{N_{p}}\) \(\Rightarrow 200V * \frac{1000}{500}\) \(\Rightarrow 400V\)

There is load resistance of 100Ω in the secondary circuit. Therefore current in the secondary

\(\Rightarrow i_{s} = \frac{V_{s}}{R_{s}}\) \(\Rightarrow \frac{400 V}{100\Omega}\) \(\Rightarrow 4 A \)

In an ideal transformer, the output power and input power are equal that is

\(\Rightarrow V_{s} * i_{s} = V_{p} * i_{p}\)

Therefore,\( i_{p} = i_{s} * \frac{V_{s}}{V_{p}} = 4 A * \frac{400V}{200V}\) \(\Rightarrow 4A * 2\) \(\Rightarrow 8A\)

Therefore, the current in the primary, assuming it to be an ideal transformer is 8 A.

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