BC = 8 m To Find: Height of the tree, which is AB
From diagram
Total height of the tree is the sum of AB and AC i.e. AB+AC
In rt ∆ABC,
BC = 8m
AB/BC = tan30°
AB/BC = 1/√3
AB = 8/√3 ——-(1)
Now,
BC/AC = cos30°
8/AC = √3/2
√3AC = 16
AC = 16/√3 ——(2)
From (1) and (2)
Height of tree = AB + AC
= 8/√3 * 16√3
= 8√3 m
8 * 1.73 = 13.84m
The height of the tree is 13.84