A triangle and parallelogram are constructed on the same base such that their area are equal. If the altitudes of the parallelogram is 100m, then find the altitude of the triangle.

Given that

A triangle and parallelogram are constructed on the same base such that their area equal.

We need to find the altitude of the triangle.

Let the triangle and parallelogram have common base b,

let the Altitude of the triangle is h1 and of parallelogram is h2(which is equal to 100 m), then

Area of triangle = 1/2×b×h1

Area of parallelogram = b X h2

As per Given,

1/2XbXh1=bXh2

1/2XbXh1=bX100

h1=200

Hence altitude of triangle= 200

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