A triangle and parallelogram are constructed on the same base such that their area equal.
We need to find the altitude of the triangle.
Let the triangle and parallelogram have common base b,
let the Altitude of the triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
Area of triangle = 1/2×b×h1
Area of parallelogram = b X h2
As per Given,
Hence altitude of triangle= 200