A trolley, while going down an inclined plane, has an acceleration of 2 cm s -2. What will be its velocity 3 s after the start?

Given that

Initial velocity (u) = 0 ( as the trolley begins from the rest position)

Acceleration (a) = 0.02 ms-2

Time (t) = 3s

Find out

velocity 3 s after the start


As per the first motion equation, v = u + at

Therefore, terminal velocity of the trolley

(v) = 0 + (0.02 ms-2)(3s)

= 0.06 ms-1

Therefore, the velocity of the trolley after 3 seconds will be 6 cm.s-1

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