CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A tuning fork is used to produce resonance in a glass tube. The length of the air column in this tube can be adjusted by a variable piston. At room temperature of 27 degree C two successive resonances are produced at 20 cm and 73 cm column length. If the frequency of the tuning fork is 320 Hz, the velocity of sound in air at 27 degree C is


A

330 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

339 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

350 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

300 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

339 m/s


Step 1: Given

Length of 1st resonance, l1=20cm=0.2m

Length of 2nd resonance, l2=73cm=0.73m

Frequency, f=320Hz

Temperature = 27o C

Step 2: Formula Used:

V=2fl2-l1

Where V velocity of sound, f is frequency, l1 is length of 1st resonance , and l2 is length of 2nd resonance.

Step 3: Calculation:

Given that two successive resonance is produced, so using the formula of resonance,

V=2fl2-l1V=2×3200.73-0.2V=640×0.53V=339.2m/s

As velocity of sound in air at 27o C is 339.2 m/s. Hence option B is correct.


flag
Suggest Corrections
thumbs-up
14
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed of Sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon