A uniform chain of length L and mass M is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is the acceleration due to gravity, the work required to pull the hanging part on to the table is

The weight of hanging part (L/3) of chain = Mg/3.

This weight acts at centre of gravity of the hanging part, which is at a distance of (L/6) from the table. Work done = force × distance

So W = (Mg/3)(L/6) = MgL/18

Related Questions & Answers
Bread Mould Reproduces Asexually By Fill In The Blank	Give An Example Of An Element That Forms Electron Deficient Compound
Explain The Principle Of Inelastic Collision	How Are Algal Blooms Caused
To Completely Describe Force Acting On A Body We Need To	What Is The Importance Of Quantum Gravity Theory
Humidity Is The Quantity Of Fill In The Blank Present In Air	Phenomenon In Which Solid Directly Changes Into Vapour Is Called
Which Element Of Group 17 Undergoes Sublimation	The Names Of Which Two Taxa Are Used In Binomial Nomenclature