# A Uniform Wire Of Resistance 50omega Is Cut Into 5 Equal Parts. These Parts Are Now Connected In Parallel. Then The Equivalent Resistance Of The Combination Is:

We know that R ∝ l

On cutting the wire into five equal parts, the length of each component becomes one-fifth and hence the resistance of each element =

$R = \frac{50}{5} = 10\Omega$

When all five wires of resistance R are connected in parallel, equivalent resistance becomes $\frac{R}{5} = \frac{10}{5} = 2 \Omega$

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