A uniformly accelerating body covers a distance of 10 m in the 3rd second and 16 m in the 6th second. What is the initial velocity and acceleration?

s = ut + (at²/2)

Equation 1 : 10 = u + (5a/2)

Equation 2 : 16 = u + (11a/2)

Solving Equation 1 and 2 we get,

a = 2 m/s²

Putting the value of a in Equation 1 we get ,

u = 5 m/s