A uniformly charged conducting sphere of 2.4m diameter has a surface density of 80.0 mu C/m^(2). (a) Find the charge on the sphere (b) What is the total electric flux leaving the surface of the sphere ?

(a) Diameter of the sphere, d = 2.4 m

Radius of the sphere, r = 1.2 m

Surface charge density, σ = 80.0 μC/m2 = 80 × 10−6 C/m2

Total charge on the surface of the sphere,

Q = Charge density × Surface area

σ x 4πr2

=80×10−6×4×3.14×(1.2)2

=1.447×10−3C

Hence, the charge on the sphere is 1.447×10−3  C.

(b) Total electric flux (ϕTotal) leaving out the surface of a sphere containing net charge Q is given by the relation,

ϕTotal =Q/εo

Permittivity of free space, εo= 8.854 × 10−12 N−1C2 m−2

Q = 1.447 × 10−3 C

Therefore,

ϕTotal=(1.447×10−3)/(8.854×10−12)

= 1.63 × 108 N C−1 m2

Hence, the total electric flux leaving the surface of the sphere is 1.63 × 108 NC−1 m2

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question