\( x = r cos \Theta \) \( y = r sin \Theta \)

Now, by substituting in \( L_{1} \), we get

\( \frac{1}{OA} = \frac{sin\Theta – cos\Theta }{10} \)

Now, by substituting in \( L_{2} \), we get

\( \frac{1}{OB} = \frac{sin\Theta – cos\Theta }{20} \) \( h = r cos \Theta \) \( k = r sin \Theta \)

Therefore, \( \frac{2}{r} = \frac{sin\Theta – cos\Theta }{10} + \frac{sin\Theta – cos\Theta }{20} \)

= 40 = \( 3(r sin \Theta ) – 3 (r cos \Theta ) \)

= 3y – 3x = 40

Therefore, the Locus Of P Is 3y – 3x = 40

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question