Question

A verandah of width $2.25m$ is constructed all along outside a room which is $5.5m$ long and $4m$ wide.

Find:

(i) the area of the verandah.

(ii) the cost of cementing the floor of the verandah at the rate of $₹200per{m}^2.$

Answer 1

Step 1: Calculate the area of the room.

The length of the room $\left(L\right)=5.5m$

The breadth of the room $\left(B\right)=4m$

Area of the room $=$ length $\times$ breadth

$$\begin{gathered} =5.5\times 4 \\ =22m^2 \end{gathered}$$

Step 2: Calculate the area of the verandah.

The new length and breadth of the room when the verandah is included are$10mand8.5m$ respectively.

A new area of the room when verandah is included $=10\times 8.5$

$=85m^2$

The area of verandah $=$ Area of the room when verandah is included $–$ Area of the room

$$\begin{gathered} =85–22 \\ =63m^2 \end{gathered}$$

Step 3: Calculate the cost of cementing the floor.

The cost of cementing the floor of the verandah at the rate of $₹200per{m}^2.$

Then the cost of cementing the $63m^2$ area of the floor of the verandah $=200\times 63$

$=₹12600$

Hence, the area of the verandah is $63m^2$ and the cost of cementing the area of the floor of the verandah is $₹12600.$