A vertical spring of force constant 100 N/m is attached with a hanging mass of 10 kg. Now an external force is applied on mass so that the spring is stretched (maximum) by additional 2 m. The work by the force F is (g=10m/s 2)

We know that work done is give by [latex]W=\frac{1}{2}kx^{2}[/latex] [latex]W=\frac{1}{2}100(2^{2})=200J[/latex]

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question