A wheel has angular acceleration of 3.0 rad/s^2 and an initial angular speed of 2.00 rad/s. In a time of 2 s it has rotated through an angle (in radian) of: (A) 6 (B) 12 (C) 10 (D) 4

Answer: (C) 10

Solution:

Initial angular speed, ω₀ =2 rad/s

Angular acceleration, α=3 rad/s²

t = 2s

Hence,

θ=ω₀t+ 1/2αt² = 2 x 2 + (1/2) x 3 x 2² = 4 + 6 = 10 radians

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