A wire fixed at the upper end stretches by length l by applying a force F. The work done in stretching is: (A) F/2l (B) Fl (C) 2F/l (D) Fl/2

Work done by a constant force in displacing the object by a distance l is given by

Work done = 1/2 x stretching force x extension in length

Work done = 1/2 x F X l

We get,

Work done = Fl/2

Therefore, the correct option is (D)

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