A works twice as fast as B. If B can complete a work in 12 days independently then the number of days in which A and B can together finish the work is?

Given, A works twice as fast as B

Thus, the ratio of work done by A and B will be 2:1

Hence, ratio of time taken will be 1:2

Now, B can complete work in 12 days.

So, work done by B in one day = 1/12

Hence, work done by A is two times of B in one day = 1/6


work done by both A and B = 1/6 + 1/12 = 3/12 = 1/4

So, the number of days to finish the work = 4


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