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Question

Ab, A2 And B2 Are Diatomic Molecules. If The Bond Enthalpies Of A2, Ab And B2 Are In The Ratio 1:1:0.5 And Enthalpy Of Formation Of Ab From A 2 And B2 Is −100 Kj Mol−1. What Is The Bond Energy Of A2?


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Solution

Step 1: Given data

Bond Enthalpies Of A2,AbAndB2 Are In The Ratio 1:1:0.5

H=-100KJ

Step 2: Deriving formula for determining bond energy

Let bond energy of A2beX, then bond energy of AB is also x

Let bond energy of B2 be x2

Enthalpy of formation ofAB is 100KJ/mol.

=A2+B2=2AB

=12A2+12B2

=AB

Step 3: Calculating Bond energy

-100=(x2+x4)-x

-100=2x+x+4x4

=400KJ

Therefore, the bond energy of A2is400KJ


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