Ab, A2 And B2 Are Diatomic Molecules. If The Bond Enthalpies Of A2, Ab And B2 Are In The Ratio 1:1:0.5 And Enthalpy Of Formation Of Ab From A 2 And B2 Is −100 Kj Mol−1. What Is The Bond Energy Of A2?

Let bond energy of A2 be X, then bond energy of AB is also x

Let bond energy of B2 be \( \frac{x}{2} \)

Enthalpy of formation of AB is − 100 KJ /mol.

=A2 + B2 =2AB

=\(\frac{1}{2}A_{2} + \frac{1}{2}B_{2} \)

=AB

\( \Delta H = -100 KJ \)

OR

=- 100 = \(  (\frac {x} {2} + \frac {x} {4}) – x  \)

=  – 100 = \( \frac {2x + x – 4x}{4} \)

= 400KJ

Therefore, the bond energy of A2 is 400KJ

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