Solution
Given
Altitudes BE and CF to sides AC and AB are equal
To Prove
(i) ΔABE ≅ ΔACF
(ii) AB = AC
Proof
(i) ΔABE ≅ ΔACF
In ∆ABF and ∆ACF,
∠E=∠F [Each 90° angle]
∠A=∠A [common angle]
AB=AC [given] S
∴∆AEB≅∆AFC [A.A.S]
(ii) AB=AC [C.P.C.T]
Hence Proved