ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if

Given:ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º

We need to find the value of ∠B

Solution:

From the properties of a parallelogram, we know that

Vertically opposite angles are equal.

Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º

∠A + ∠B= 180º

105 +∠B =180º

∠B=180º-105º

∠B=75º

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