Air Contains 23 Percent Of Oxygen And 77 Percent Of Nitrogen By Weight. What Is The Percentage Of Oxygen By Volume Is

Let the mixture of air be 100g.

Mass of Oxygen (O₂) in 100 g of air = 23 g

The molar mass of Oxygen = 32 g

If one mole of Oxygen occupies 22.4 L volume.

Then 23g of oxygen occupies =\( \frac{22.4}{32} * 23 = 16.1L\)

Mass of Nitrogen in 100 g of air = 77 g

The molar mass of Nitrogen (N₂) = 28 g

If one mole of Nitrogen occupies 22.4 L volume.

Then 77g of Nitrogen occupies = \( \frac{22.4}{28} * 77 = 61.6L\)

Now total volume of air = 16.1L + 61.6L = 77.7 L

The percentage of Oxygen =\(\frac{16.1}{77.7} * 100 = 20.7%\)

The percentage of Oxygen By Volume Is 20.7 percentage.

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question