An Ac Source Is Rated At 220V, 50Hz. The Time Taken For Voltage To Change From Its Peak Value To Zero Is____.

The time taken for voltage to change from its peak value to zero is:

 

The time taken for voltage to change from its peak value to zero

\( (\frac{T}{2}) – (\frac{T}{4}) = (\frac{2T}{8}) = (\frac{T}{4}) \)

As given:

f= 50 Hz

\( \Rightarrow T = \frac{1}{50} \) sec

\( \Rightarrow T = \frac{T}{4} \) \( \Rightarrow\frac{1}{50 * 4} \) \( \Rightarrow \frac{1}{200} \) \( \Rightarrow 5 * 10^{-3} \) sec

Therefore, the time taken for voltage to change from its peak value to zero is: \( 5 * 10^{-3} \)sec

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