An air bubble in a glass slab with a refractive index of 1.5 (near-normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

Given, l = length of the slab x = position of air bubble from one side the total apparent length of slab = 5 + 3 \(\frac{x}{\mu }+(\frac{l-x}{\mu })=8\) \((\frac{l}{\mu })=8\) \(l=8\mu =8*15=12 cms\)

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