The correct answer is (A) 480μc.
Initial charge qi = CV
= 10 (12) = 120μC.
After being filled with dielectric liquid, the charge q′ = C′V = KCV.
=5(10)12 = 600μC.
The (additional) charge that flows now from the battery to the capacitor
= qf – qi
= 600 – 120 = 480μC.
Therefore, it is proved.
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