The correct answer is (A) 480μc.

Initial charge qi = CV

= 10 (12) = 120μC.

After being filled with dielectric liquid, the charge q′ = C′V = KCV.

=5(10)12 = 600μC.

The (additional) charge that flows now from the battery to the capacitor

= qf – qi

= 600 – 120 = 480μC.

Therefore, it is proved.

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