An arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirrror of focal length of 20 cm. Find the nature, position and size of the image formed

Given

H1 = 2.5 cm

u = -25 cm

f = 20 cm

Using the mirror formula, we get,

1/f = 1/v + 1/u

On substituting, we get

1/20 = 1/v – 1/25

1/v = 1/20 + 1/25

We get,

1/v = 9/100

v = 11.11 cm

m = h2 / h1

m = -v/u

h2 / 2.5 = -11.11/-25

We get,

h2 = 1.11 cm

Therefore, the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11 cm size.

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