Torque, P E sin\(\Theta= 2 Q l sin\Theta\)


Q is the charge

E is the electric field

l is the length of the dipole

Potential energy, U = \(-P E cos\Theta = – 2 Ql cos \Theta \) \(\frac{\tau}{U} = \frac{2Qlsin\Theta}{-2Qlsin\Theta} \) \(\Rightarrow -tan\Theta \) \(\frac{\tau}{U} = -tan\Theta \) \(U = – \frac{\tau}{-tan 60^{\circ}} \) \(\Rightarrow \frac{8\sqrt{3}}{\sqrt{3}} \) \(\Rightarrow -8 joule. \)

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