An electric lamp of 100 ?, a toaster of resistance. 50 ?, and a water filter of resistance 500 ? are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all to the same source that takes as much current as all three appliances, and what is current through it

Given

R₁ = 100 Ω, R₂ = 50 Ω and R₃ = 500 Ω

We needto find total resistance and current

Total resistance= 1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/100 Ω + 1/50 Ω + 1/500 Ω

1/R = ( 5 + 10 + 1 )/500

1/R = 16/500

500/16 = Total R

Total Resistance = 500/16 Ω

Since, R = V/I from ohm’s law

500/16 = 220/I

I = 220 × 16/500

I = 7.04 A

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