Question

An electric oven of 2 kW power rating is operated in a domestic electric circuit that has a current rating of 5A. If the supply voltage is 220V, what result do you expect? Explain.

Answer 1

Power

1. Power is the work done by a body in unit time.
2. Power is defined by the form, $P=VI$, where, V is the voltage and I is the current through the circuit.

Step 1: Given data

The power rating of the oven is, $P=2kw.$

The fuse rating of the circuit is, $5A.$

Supplied voltage is, V = $220volt.$

Step 2: Calculation of current

We know, power is, $P=VI$.

So,

$$\begin{gathered} I=\frac{P}{V}=\frac{2kw}{220volt}=\frac{2000w}{220volt} \\ orI=9.1A. \end{gathered}$$

It is clear that the above current ($9.1A$) exceeds the fuse rating ($5A$) of the given circuit. So the fuse will be broken due to high current flow, through the circuit.