An Electron, In A Hydrogen Atom, In Its Ground State Absorbs 1.5 Times As Much Energy As The Minimum Required For Its Escape (I.E., 13.6ev) From The Atom. Calculate The Value Of Λ For The Emitted Electron.

Energy observed = 13.6 * 1.5 = 20.4eV

Energy required = 13.6eV

Therefore, excess energy = 6.8e V = 6.8 * 1.6 – \(10^{-19} J = Ke \) \(\lambda = \frac{h}{mc} \) \(\Rightarrow \lambda = \frac{h}{\sqrt{2mk}} \) \(\Rightarrow \frac{6.626 * 10^{-34}}{\sqrt{2 * 9.1 * 10^{-31} * 6.8 * 1.6 * 10^{-19}}} \) \(\Rightarrow \lambda = 4.7 A° \)

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