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Question

An element X which is a yellow solid at room temperature shows catenation and allotropy. X forms two oxides which are also formed during the thermal decomposition of ferrous sulphate crystals and are the major air pollutants.

(a) Identify the element X

(b) Write the electronic configuration of X

(c) Write the balanced chemical equation for the thermal decomposition of ferrous sulphate crystals?

(d) What would be the nature (acidic/ basic) of oxides formed?

(e) Locate the position of the element in the Modern Periodic Table.


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Solution

(a) Identification of the element X

  • Element X is Sulphur (S)

(b) Electronic configuration of the identified element

  • Atomic number of Sulphur= 16
  • Electronic configuration= 1s22s22p63s23p4

(c) Balanced chemical equation for the thermal decomposition of ferrous sulphate crystals

2FeSO4(s)(Ferroussulphate)HeatFe2O3(s)(Ferricoxide)+SO2(g)(Sulphurdioxide)+SO3(g)(Sulphurtrioxide)

(d) Nature (acidic/ basic) of oxides formed

Oxides formed are Sulphur dioxide (SO2) and Sulphur trioxide (SO3) which are acidic in nature as they furnish an acid on reaction with water.

(e) Position of the element in the Modern Periodic Table

  • As last electron entered in the p-subshell, so Sulphur is a p-block element.
  • Period is located by identifying the highest value of n (principal quantum number) which is 3 here. So period is 3.
  • For the group of a p block element= 12+ number of electrons in p-subshell
  • Therefore, group= 12+ 4= 16
  • Hence, Sulphur belongs to Period= 4, p- block, group-16 in the modern periodic table.

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