An ideal refrigerator has a freezer at a temperature of -13°C, The coefficient of performance of the engine is 5. The temperature of the air to which heat is rejected will be

(a) 325°C
(b) 39°C
(c) 325 K
(d) 320°C
Correct option: (b) 39°C
Given, temperature of freezer = T2 = –13°C = –13 + 273 = 260 K
Coefficient of performance = β = 5
We know that β = [T2 / (T1 – T2)]
5 = [(260) / (T1 – 260)]
T1 = 260 + 52
= 312 K
= (312 – 273)°C
= 39°C

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