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Question

An ideal refrigerator has a freezer at a temperature of -13°C, The coefficient of performance of the engine is 5. The temperature of the air to which heat is rejected will be


A

325°C

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B

39°C

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C

325K

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D

320°C

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Solution

The correct option is B

39°C


Explanation for the correct option

Option B: 39°C

Step 1: Given data

The temperature of the refrigerator = -13°C=-13+273=260K

The coefficient of performance of the engine = η=5

Step 2: Formula used

The formula for the coefficient of performance of the engine is: η=T2T1-T2where

T2=lowtemperatureT1=hightemperature

Step 3: Calculations

The temperature of the air outside will be higher than the temperature of the freezer.

Hence, T1=temperatureofair and T2=temperatureoffreezer=260K

Putting the values in the formula for the coefficient of performance

5=260T1-2605T1-1300=2605T1=1560T1=312KT1=312-273=39°C

Hence the temperature of the air to which heat will be rejected is 39°C. Hence this option is correct.


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