An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

Radius of curvature (R) = 30 cm
f = R/2 = 30/2 = 15 cm
u = -20 cm,
h= 5 cm.
1/v +1/u = 1/f
1/v = 1/15+ 1/20 = 7/60
v = 60/7 = 8.6 cm.
Image is virtual and erect and formed behind the mirror.
hi/h0= v/u
hi/5= 8.6/20
hi = 2.2 cm.
Size of image is 2.2 cm.

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