 # An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?

When two objects fall with the same acceleration simultaneously, after 2 seconds the difference in their heights will not change and it remains 50 m.

d1 = h1 – s1

d1 = 150 – 1/2at2

d1 = 150 – [1/2 × 10 × 4]

d1 = 150 – 20

d1 = 130 m

Therefore the height of the first object after 2 seconds is 130 m.

In the same way, the height of the second object is

d2 = h2 – s2

d2 = 100 – 1/2 at2

d2 = 100 – [1/2 × 10 × 4]

d2 =100 – 20

d2 = 80 m

Therefore, the height of the second object after 2 seconds is 80 m.

d1 – d2 = 130 m – 80 m

d1 – d2 = 50 m

So, the difference is the same, i.e. 50 m.

This concludes that the difference in height of the two objects does not depend on time and will always be the same. (0) (0)