An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of image.

The focal length f = +15 cm,

Object distance u = -10 cm

From mirror formula

1/f = 1/v +1/u

1/v = 1/15 +1/10

1/v = 5/30

v = + 6 cm

The image is formed 6 cm behind the mirror; it is a virtual and erect image

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