An object is placed at a distance of 10cm from a diverging mirror of focal length 15 cm . Find the position and of the image formed also calculate the magnification of the image .

The given parameters are U= -10 cm

f= 15 cm

1/f = 1/v + 1/u

So, 1/v= 1/f – 1/u

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Therefore v=5/30 = 6 cm

Hence the image is formed behind the mirror and therefore it is virtual and erect

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