An Object Is Placed At A Distance Of 20cm From The Pole Of A Concave Mirror Of Focal Length 10cm. The Distance Of The Image Formed Is?

Given

\(\begin{array}{l} \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \end{array} \)

=

\(\begin{array}{l} \frac{1}{v} + \frac{1}{-20} = \frac{-1}{10} \end{array} \)

=

\(\begin{array}{l} \frac{1}{v} = -\frac{-1}{10} + \frac{1}{-20} \end{array} \)

=

\(\begin{array}{l} \frac{1}{v} = \frac{-2 + 1}{20} \end{array} \)

=

\(\begin{array}{l} \frac{-1}{20} \end{array} \)

v = -20cm

The distance of the image formed is-20cm and the nature of the image: Virtual

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