Given
\(\begin{array}{l} \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \end{array} \)
=
\(\begin{array}{l} \frac{1}{v} + \frac{1}{-20} = \frac{-1}{10} \end{array} \)
=
\(\begin{array}{l} \frac{1}{v} = -\frac{-1}{10} + \frac{1}{-20} \end{array} \)
=
\(\begin{array}{l} \frac{1}{v} = \frac{-2 + 1}{20} \end{array} \)
=
\(\begin{array}{l} \frac{-1}{20} \end{array} \)
v = -20cm
The distance of the image formed is-20cm and the nature of the image: Virtual
Explore more such questions and answers at BYJU’S.
