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An object moving with 6m per second execute an acceleration 2m/s^2 in the next 3 seconds. How much distance did it cover?

we have initial velocity equals to 6 metres per second and acceleration is equals to 2 metres per second square and time is given equals to 3 seconds on applying the formula we get

s= 6×3+1/2×2×9

s=18+9×1

s=27 metres

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