An oxide of sulphur contains 50% of sulphur in it. Its empirical formula is :

For sulphur, the percentage of sulphur divided by its molar mass gives = 50/32=1.56 For oxygen, the percentage of sulphur divided by its molar mass = 50/16= 3.12 It is clear that it is in 1:2 ratio. Hence, the emperial formula is SO2.

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