Question

Arrange the following in descending order:

$\frac{1}{5},\frac{3}{7},\frac{7}{10}$

Answer 1

Step $1$: Find LCM of denominators of all the given fractions:

$\therefore$ LCM $\left(5,7,10\right)=70$

Step 2: Multiply numerator and denominator of each fraction by a suitable number so that denominator in each case becomes equal to LCM obtained in Step $1$:

$\therefore$ $\frac{1}{5}=\frac{1\times 14}{5\times 14}=\frac{14}{70}$

$\frac{3}{7}=\frac{3\times 10}{7\times 10}=\frac{30}{70}$

$\frac{7}{10}=\frac{7\times 7}{10\times 7}=\frac{49}{70}$

Step 3: Step $2$ would convert all fractions to like fractions and therefore the fraction with greater numerator is greater:

$\because$ $49>30>14$

$\therefore$ $\frac{7}{10}>\frac{3}{7}>\frac{1}{5}$

Therefore, the descending order of fractions is: $\frac{7}{10},\frac{3}{7},\frac{1}{5}$