Question

At a certain place, horizontal component is $\sqrt{3}$ times the vertical component, the angle of dip at this place is.

• A. $0$
• B. $\frac{\mathrm{\pi }}{3}$
• C. $\frac{\mathrm{\pi }}{6}$
• D. none of these

Answer 1

The correct option is C

$\frac{\mathrm{\pi }}{6}$

Given,

horizontal component $=\sqrt{3}$ times the vertical component

$B_H=\sqrt{3}{B}_V$

$\tan \alpha =\frac{B_V}{B_H}$

$$\begin{gathered} =\frac{B_V}{\sqrt{3}{B}_V} \\ =\frac{1}{\sqrt{3}} \end{gathered}$$

$\tan \alpha =\frac{1}{\sqrt{3}}$

$\alpha =30°=\frac{\mathrm{\pi }}{6}$

Hence, option (C) is the correct option.