At The Height of 80M, An Aeroplane Is Moving With 150 Ms−1. A Bomb Is Dropped From It, So As To Hit A Target. At What Distance From The Target Should Bomb Be Dropped? (G=10Ms −2).

Given

Speed of aeroplane = 150 m/s

Height of the plane from the surface = 80 m

The horizontal distance BC covered by the bomb = \( v_{H} * \sqrt{\frac{2h}{g}} \) \( \Rightarrow 150 * \sqrt{\frac{2 * 80}{10}} \) \( \Rightarrow 150 * 4 = 600m \)

Now the distance between the target and dropping point of the bomb \( AC = \sqrt{BC^{2} + AB^{2}} \) \( \Rightarrow \sqrt{600^{2} + 80^{2}} \) \( \Rightarrow 605.3m \)

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