Question

Baichung’s father is $26years$ younger than Baichung’s grandfather and $29years$ older than Baichung. The sum of the ages of all the three is $135years$. What is the age of each one of them?

Answer 1

Step 1: Form an appropriate equation based on the given information

Let age of Baichung's father be $n$ years

Then, age of Baichung’s grandfather $=(n+26)$ years

and, Age of Baichung $=(n–29)$ years

According to the given details the equation becomes

$n+(n+26)+(n–29)=135$

Step 2: Solve above equation for $n$

$3n+26–29=135$

$3n–3=135$

$3n=135+3$

$3n=138$

$n=\frac{138}{3}$

$n=46$

Age of Baichung’s father $=n=46$

Age of Baichung’s grandfather $=(n+26)=46+26=72$

Age of Baichung $=(n–29)=46–29=17$

Hence,

Age of Baichung’s father $=46$

Age of Baichung’s grandfather $=72$

Age of Baichung $=17$