Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution

Let age of Baichung’s father be ‘n’.

Then, age of Baichung’s grandfather = (n + 26)

and, Age of Baichung = (n – 29)

According to the given details the equation becomes

n + (n + 26) + (n – 29) = 135

3n+ 26 – 29 = 135

3n – 3 = 135

3n = 135 + 3

3n = 138

n = 138/3

n = 46

Age of Baichung’s father = n = 46

Age of Baichung’s grandfather = (n + 26) = 46 + 26 = 72

Age of Baichung = (n – 29) = 46 – 29 = 17

Answer

Age of Baichung’s father = 46

Age of Baichung’s grandfather = 72

Age of Baichung = 17

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