Question

${\mathrm{BF}}_3$ is _______.

• A. Lewis Acid
• B. Ionic Compound
• C. Electron Deficient Compound
• D. Both (A) And (C)

Answer 1

The correct option is D

Both (A) And (C)

Explanation of the correct option:

Option D:

1. ${\mathrm{BF}}_3$ is a lewis acid.
2. Boron in ${\mathrm{BF}}_3$ has an unfilled orbital and a deficiency in electrons. It becomes a Lewis acid as a result of accepting two electrons.
3. ${\mathrm{BF}}_3$ is an electron-deficient molecule.
4. With the help of three single covalent connections with fluorine, the boron (B) atom gains three more electrons, bringing its total number of electrons up to six.
5. Because it needs two more electrons to complete its octet, boron (B) takes a single pair from fluorine (F) through a coordinating covalent bond.

Explanation of the incorrect answers:

Options B:

1. Because it is created by exchanging electrons, ${\mathrm{BF}}_3$, is a covalent molecule.

Hence, option D is correct, i.e., Both (A) And (C).