Calculate the amount of benzoic acid ( $C_{6} H_{5} COOH$ ) required for preparing 250 ml of 0.15 M solution in methanol.

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Solution

Calculation of the amount of benzoic acid
Step 1: Calculation of the number of moles of benzoic acid
$M o l a r i t y = \frac{N u m b e r o f m o l e s o f s o l u t e}{V o l u m e o f s o l u t i o n i n l i t e r s}$
No.of moles of benzoic acid required = $\frac{0.15 x 250}{1000}$
No.of moles of benzoic acid required = 0.0375 moles
Calculating the molar mass of benzoic acid
Molar mass of benzoic acid = $7 (12) + 6 (1) + 2 (16)$
Molar mass of benzoic acid $= 84 + 6 + 32$
Molar mass of benzoic acid = 122 g/mol
Calculation of the mass of benzoic acid
Mass of benzoic acid required = $122 \times 0.0375$
Mass of benzoic acid required = 4.575 g
Therefore the amount of benzoic acid required is 4.575 g.

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Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250 ml of 0.15 M solution in methanol.

Calculate the amount of benzoic acid ( $C_{6} H_{5} COOH$ ) required for preparing 250 ml of 0.15 M solution in methanol.