Calculate the amount of charge flowing in 2 min in a wire of resistance 10Ω when a potential difference of 20V is applied between its ends.

Given, t = 2 min = 120 second R=10Ω, V = 20 volt We know that, I=V/R = 20/10 = 2 A Charge 2 = i*t = 2 *120 = 240 coulomb

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