Calculate the amount of oxalic acid used to prepare 100 ml of 0.1n and 0.1m solution

Molarity = weight*1000/molecular weight*vol

Oxalic acid = COOH.COOH.2H2O

Molecular weight = 126g/mol

n factor=2

weight = ?

Molarity M = 0.1

volume = 100mL

Therefore 0.1 = x * 1000/ 126*100

x = 1.26

In normality

Normality = weight*1000/Equivalent weight*vol

Equivalent weight = 63g/mol

0.1 = x *1000/63*100

x = 0.63g

Was this answer helpful?

  
   

4 (6)

Upvote (6)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

BOOK

Free Class

Ask
Question