Calculate the area of the designed region in Fig. common between the two quadrants of circles of radius 8 cm each.

Ncert solution class 10 chapter 12-27

Solution

AB = BC = CD = AD = 8 cm

Area of ΔABC = Area of ΔADC 

Area of triangle=(½)×8×8 = 32 cm2

Area of quadrant AECB = Area of quadrant AFCD = (¼)×22/7×82

= 352/7 cm2

Area of shaded region = (Area of quadrant AECB – Area of ΔABC) = (Area of quadrant AFCD – Area of ΔADC)

= (352/7 -32)+(352/7- 32) cm2

= 2×(352/7-32) cm2

= 256/7 cm2

= 36.57cm2

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