# Two point charges q1 and q2 of magnitude +10-8 C and -10-8 C respectively are placed 0.1 m apart. Calculate the electric field at point A.B & C.

The electric field at point A = electric field due to q<sub>1</sub> + electric field due to q<sub>2</sub> = 72000 N/C

The electric field at point B = electric field due to q<sub>1</sub> – electric field due to q<sub>2</sub> = 32000 N/C

The electric field at point C = $sqrt{E_{1}^{2}+E_{2}^{2}+2E_{1}.E_{2}costheta }$ = 9000 N/C