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Question

Calculate the freezing point of a solution containing 60g of Glucose (Molar Mass =180 g Mol−1) In 250 g of water.


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Solution

Step 1: Calculation of the number of moles of glucose
Numberofmolesofglucose=GivenmassofglucoseMolecularmassofglucose
Numberofmolesofglucose=60g180gmol
Number of moles of glucose = 0.333 mol

Step 2: Calculation of molality of glucose
Molality=NumberofmolesofsoluteMassofsolventinKg
Molality=0.333mol250g×1kg1000gMolality=1.333molkg

Step 3: Determination of depression in freezing point
Tf=Kf×m
The value of molal depression constant =1.86gmol-1K
Tf=1.86gmol-1K×1.33molkg-1Tf=2.48K

Step 4: Calculation of freezing point of glucose solution
The freezing point of pure water = 273.2 K
The freezing point of a solution containing 60g of glucose in 250 g of water. = 273.2K-2.48K
The freezing point of a solution containing 60g of glucose in 250 g of water. = 270.72K

Hence the freezing point of a solution containing 60g of Glucose In 250 g of water is 270.72 K


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