Calculate the molality of 12.5% w/w sulphuric acid?

12.5% w/w means 12.5 g in 100 g of solution.
Weight of solvent = 100 g €“ 12.5 g= 87.5 g. Number of moles of sulphuric acid = 12.5/ 98 =0.127 mol
So molality = 0.127×1000/87.5 = 1.45 m

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